MathDB
3 equal angles via projections on isosceles triangle

Source: JBMO Shortlist 2005

January 1, 2018
geometryisoscelesequal angles

Problem Statement

Let ABCABC be an isosceles triangle (AB=AC)(AB=AC) so that A<2B\angle A< 2 \angle B . Let D,ZD,Z points on the extension of height AMAM so that CBD=A\angle CBD = \angle A and ZBA=90\angle ZBA = 90^\circ. Let EE the orthogonal projection of MM on height BFBF, and let KK the orthogonal projection of ZZ on AEAE. Prove that KDZ=KDB=KZB \angle KDZ = \angle KDB = \angle KZB.