Let ABC be an isosceles triangle (AB=AC) so that ∠A<2∠B . Let D,Z points on the extension of height AM so that ∠CBD=∠A and ∠ZBA=90∘. Let E the orthogonal projection of M on height BF, and let K the orthogonal projection of Z on AE. Prove that ∠KDZ=∠KDB=∠KZB.
geometryisoscelesequal angles