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2014 JBMO Shortlist
1
n+ \lfloor \sqrt{n} \rfloor+\lfloor \sqrt[3]{n} \rfloor=2014
n+ \lfloor \sqrt{n} \rfloor+\lfloor \sqrt[3]{n} \rfloor=2014
Source: JBMO Shortlist 2014 A1
April 24, 2019
algebra
floor function
Floor
equation
positive real
Problem Statement
Solve in positive real numbers:
n
+
⌊
n
⌋
+
⌊
n
3
⌋
=
2014
n+ \lfloor \sqrt{n} \rfloor+\lfloor \sqrt[3]{n} \rfloor=2014
n
+
⌊
n
⌋
+
⌊
3
n
⌋
=
2014
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