A box contains 3 shiny pennies and 4 dull pennies. One by one, pennies are drawn at random from the box and not replaced. If the probability is ba that it will take more than four draws until the third shiny penny appears and ba is in lowest terms, then a+b=<spanclass=′latex−bold′>(A)</span>11<spanclass=′latex−bold′>(B)</span>20<spanclass=′latex−bold′>(C)</span>35<spanclass=′latex−bold′>(D)</span>58<spanclass=′latex−bold′>(E)</span>66