Through a point P inside the triangle ABC a line is drawn parallel to the base AB, dividing the triangle into two equal areas. If the altitude to AB has a length of 1, then the distance from P to AB is:
<spanclass=′latex−bold′>(A)</span>21<spanclass=′latex−bold′>(B)</span>41<spanclass=′latex−bold′>(C)</span>2−2<spanclass=′latex−bold′>(D)</span>22−2<spanclass=′latex−bold′>(E)</span>82+2