MathDB
2004 Algebra #4

Source:

December 26, 2011
floor function

Problem Statement

Evaluate the sum 121+1+122+1+123+1++12100+1 \dfrac {1}{2 \lfloor \sqrt {1} \rfloor + 1} + \dfrac {1}{2 \lfloor \sqrt {2} \rfloor + 1} + \dfrac {1}{2 \lfloor \sqrt {3} \rfloor + 1} + \cdots + \dfrac {1}{2 \lfloor \sqrt {100} \rfloor + 1}