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2013 CHMMC Tiebreaker 4 - sum1/2+1/2x3+ 1/2x3x5 + ....

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March 1, 2024
algebraCHMMC

Problem Statement

Let A=12+13+15+19,A =\frac12 +\frac13 +\frac15 +\frac19, B=123+125+129+135+139+159,B =\frac{1}{2 \cdot 3}+\frac{1}{2 \cdot 5}+\frac{1}{2 \cdot 9}+\frac{1}{3 \cdot 5}+\frac{1}{3 \cdot 9} +\frac{1}{5 \cdot 9}, C=1235+1239+1259+1359.C =\frac{1}{2 \cdot 3 \cdot 5} + \frac{1}{2 \cdot 3 \cdot 9} + \frac{1}{2 \cdot 5 \cdot 9} +\frac{1}{3 \cdot 5 \cdot 9}. Compute the value of A+B+CA + B + C.