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Today's calculation of Integral 739

Source: 2011 Kagoshima University entrance exam/Education

July 5, 2011
calculusintegrationfunctiontrigonometryderivativealgebrafunctional equation

Problem Statement

Find the function f(x)f(x) such that : f(x)=cos⁡x+∫02πf(y)sin⁡(x−y) dyf(x)=\cos x+\int_0^{2\pi} f(y)\sin (x-y)\ dy
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