MathDB

739

Part of 2011 Today's Calculation Of Integral

Problems(1)

Today's calculation of Integral 739

Source: 2011 Kagoshima University entrance exam/Education

7/5/2011
Find the function f(x)f(x) such that : f(x)=cos⁡x+∫02πf(y)sin⁡(x−y) dyf(x)=\cos x+\int_0^{2\pi} f(y)\sin (x-y)\ dy
calculusintegrationfunctiontrigonometryderivativealgebrafunctional equation