A positive integer n satisfies the equation (n+1)!+(n+2)!=n!⋅440. What is the sum of the digits of n?<spanclass=′latex−bold′>(A)</span>2<spanclass=′latex−bold′>(B)</span>5<spanclass=′latex−bold′>(C)</span>10<spanclass=′latex−bold′>(D)</span>12<spanclass=′latex−bold′>(E)</span>15