MathDB
AMC 8 2004 Problem 11

Source:

July 22, 2011

Problem Statement

The numbers -2, 4, 6, 9 and 12 are rearranged according to these rules:
1. The largest isn't first, but it is in one of the first three places. 2. The smallest isn't last, but it is in one of the last three places. 3. The median isn't first or last.
What is the average of the first and last numbers?
<spanclass=latexbold>(A)</span>3.5<spanclass=latexbold>(B)</span>5<spanclass=latexbold>(C)</span>6.5<spanclass=latexbold>(D)</span>7.5<spanclass=latexbold>(E)</span>8<span class='latex-bold'>(A)</span>\: 3.5 \qquad<span class='latex-bold'>(B)</span> \:5 \qquad<span class='latex-bold'>(C)</span> \:6.5 \qquad<span class='latex-bold'>(D)</span> \:7.5 \qquad<span class='latex-bold'>(E)</span> \:8