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Choosing x

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January 11, 2009
logarithmslimitfunction

Problem Statement

It is possible to choose x>23 x > \frac {2}{3} in such a way that the value of \log_{10}(x^2 \plus{} 3) \minus{} 2 \log_{10}x is <spanclass=′latex−bold′>(A)</span> negative<spanclass=′latex−bold′>(B)</span> zero<spanclass=′latex−bold′>(C)</span> one <span class='latex-bold'>(A)</span>\ \text{negative} \qquad <span class='latex-bold'>(B)</span>\ \text{zero} \qquad <span class='latex-bold'>(C)</span>\ \text{one} <spanclass=′latex−bold′>(D)</span> smaller than any positive number that might be specified <span class='latex-bold'>(D)</span>\ \text{smaller than any positive number that might be specified} <spanclass=′latex−bold′>(E)</span> greater than any positive number that might be specified <span class='latex-bold'>(E)</span>\ \text{greater than any positive number that might be specified}
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