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Problems
Contests
National and Regional Contests
USA Contests
MAA AMC
AMC 12/AHSME
1965 AMC 12/AHSME
21
21
Part of
1965 AMC 12/AHSME
Problems
(1)
Choosing x
Source:
1/11/2009
It is possible to choose
x
>
2
3
x > \frac {2}{3}
x
>
3
2
in such a way that the value of \log_{10}(x^2 \plus{} 3) \minus{} 2 \log_{10}x is
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A
)
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negative
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zero
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one
<span class='latex-bold'>(A)</span>\ \text{negative} \qquad <span class='latex-bold'>(B)</span>\ \text{zero} \qquad <span class='latex-bold'>(C)</span>\ \text{one}
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A
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<
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negative
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B
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<
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zero
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C
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<
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one
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D
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smaller than any positive number that might be specified
<span class='latex-bold'>(D)</span>\ \text{smaller than any positive number that might be specified}
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D
)
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smaller than any positive number that might be specified
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E
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greater than any positive number that might be specified
<span class='latex-bold'>(E)</span>\ \text{greater than any positive number that might be specified}
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(
E
)
<
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greater than any positive number that might be specified
logarithms
limit
function