MathDB
Absolute Value

Source:

January 24, 2006
absolute value

Problem Statement

If |x \minus{} 2| \equal{} p, where x<2 x < 2, then x \minus{} p \equal{} (A)\minus{}\!2 \qquad (B)\ 2 \qquad (C)\ 2 \minus{} 2p \qquad (D)\ 2p \minus{} 2\qquad (E)\ |2p \minus{} 2|