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Today's Calculation Of Integral
2010 Today's Calculation Of Integral
627
Today's calculation of Integral 627
Today's calculation of Integral 627
Source:
July 8, 2010
calculus
integration
trigonometry
logarithms
calculus computations
Problem Statement
Evaluate
∫
π
4
π
3
(
2
sin
θ
+
1
)
cos
3
θ
(
sin
2
θ
+
1
)
2
d
θ
.
\int_{\frac{\pi}{4}}^{\frac{\pi}{3}} \frac{(2\sin \theta +1)\cos ^ 3 \theta}{(\sin ^ 2 \theta +1)^2}d\theta .
∫
4
π
3
π
(
s
i
n
2
θ
+
1
)
2
(
2
s
i
n
θ
+
1
)
c
o
s
3
θ
d
θ
.
Proposed by kunny
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