MathDB
Problems
Contests
National and Regional Contests
Japan Contests
Today's Calculation Of Integral
2010 Today's Calculation Of Integral
627
627
Part of
2010 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 627
Source:
7/8/2010
Evaluate
∫
π
4
π
3
(
2
sin
θ
+
1
)
cos
3
θ
(
sin
2
θ
+
1
)
2
d
θ
.
\int_{\frac{\pi}{4}}^{\frac{\pi}{3}} \frac{(2\sin \theta +1)\cos ^ 3 \theta}{(\sin ^ 2 \theta +1)^2}d\theta .
∫
4
π
3
π
(
s
i
n
2
θ
+
1
)
2
(
2
s
i
n
θ
+
1
)
c
o
s
3
θ
d
θ
.
Proposed by kunny
calculus
integration
trigonometry
logarithms
calculus computations