Today's calculation of Integral 250
Source:
December 9, 2007
calculusintegrationlimittrigonometrycalculus computations
Problem Statement
For a positive constant number , find \lim_{n\to\infty} \frac {1}{n^{p \plus{} 1}}\sum_{k \equal{} 0}^{n \minus{} 1} \int_{2k\pi}^{(2k \plus{} 1)\pi} x^p\sin ^ 3 x\cos ^ 2x\ dx.