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250

Part of 2007 Today's Calculation Of Integral

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Today's calculation of Integral 250

Source:

12/9/2007
For a positive constant number p p, find \lim_{n\to\infty} \frac {1}{n^{p \plus{} 1}}\sum_{k \equal{} 0}^{n \minus{} 1} \int_{2k\pi}^{(2k \plus{} 1)\pi} x^p\sin ^ 3 x\cos ^ 2x\ dx.
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