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India LIMIT
2019 LIMIT
2019 LIMIT Category C
Problem 12
limit of x[1/x] x->0
limit of x[1/x] x->0
Source: LIMIT 2019 CCS1 P12
April 28, 2021
real analysis
Problem Statement
lim
x
→
0
x
⌊
1
x
⌋
=
?
\lim_{x\to0}x\left\lfloor\frac1x\right\rfloor=?
lim
x
→
0
x
⌊
x
1
⌋
=
?
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