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2022 AIME Problems
6
Maximum Difference
Maximum Difference
Source: 2022 AIME II Problem 6
February 17, 2022
AMC
AIME
AIME I
Problem Statement
Let
x
1
≤
x
2
≤
⋯
≤
x
100
x_1\leq x_2\leq \cdots\leq x_{100}
x
1
≤
x
2
≤
⋯
≤
x
100
be real numbers such that
∣
x
1
∣
+
∣
x
2
∣
+
⋯
+
∣
x
100
∣
=
1
|x_1| + |x_2| + \cdots + |x_{100}| = 1
∣
x
1
∣
+
∣
x
2
∣
+
⋯
+
∣
x
100
∣
=
1
and
x
1
+
x
2
+
⋯
+
x
100
=
0
x_1 + x_2 + \cdots + x_{100} = 0
x
1
+
x
2
+
⋯
+
x
100
=
0
. Among all such
100
100
100
-tuples of numbers, the greatest value that
x
76
−
x
16
x_{76} - x_{16}
x
76
−
x
16
can achieve is
m
n
\tfrac mn
n
m
, where
m
m
m
and
n
n
n
are relatively prime positive integers. Find
m
+
n
m+n
m
+
n
.
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