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F = Ma
2010 F = Ma
15
15
Part of
2010 F = Ma
Problems
(1)
2010 F = Ma Exam Problem 15
Source:
8/29/2019
A small block moving with initial speed
v
0
v_\text{0}
v
0
moves smoothly onto a sloped big block of mass
M
M
M
. After the small block reaches the height
h
h
h
on the slope, it slides down. Find the height
h
h
h
.(A)
h
=
v
0
2
2
g
h=\frac{v_\text{0}^2}{2g}
h
=
2
g
v
0
2
(B)
h
=
1
g
M
v
0
2
m
+
M
h=\frac{1}{g}\frac{Mv_\text{0}^2}{m+M}
h
=
g
1
m
+
M
M
v
0
2
(C)
h
=
1
2
g
M
v
0
2
m
+
M
h=\frac{1}{2g}\frac{Mv_\text{0}^2}{m+M}
h
=
2
g
1
m
+
M
M
v
0
2
(D)
h
=
1
2
g
m
v
0
2
m
+
M
h=\frac{1}{2g}\frac{mv_\text{0}^2}{m+M}
h
=
2
g
1
m
+
M
m
v
0
2
(e)
h
=
v
0
2
g
h=\frac{v_\text{0}^2}{g}
h
=
g
v
0
2
2010
Problem 15