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CNCM Online Round 2
6
6
Part of
CNCM Online Round 2
Problems
(1)
CNCM Online R2P6
Source:
8/8/2020
Let
S
S
S
be the set of all ordered pairs
(
x
,
y
)
(x,y)
(
x
,
y
)
of integer solutions to the equation
6
x
2
+
y
2
+
6
x
=
3
x
y
+
6
y
+
x
2
y
.
6x^2+y^2+6x=3xy+6y+x^2y.
6
x
2
+
y
2
+
6
x
=
3
x
y
+
6
y
+
x
2
y
.
S
S
S
contains a unique ordered pair
(
a
,
b
)
(a,b)
(
a
,
b
)
with a maximal value of
b
b
b
. Compute
a
+
b
a+b
a
+
b
. Proposed by Kenan Hasanaliyev (claserken)
CNCM
Problem Discussion