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MAA AMC
AMC 8
2024 AMC 8 -
15
15
Part of
2024 AMC 8 -
Problems
(1)
FLYFLYFLYBUGBUGBUG
Source: 2024 AMC 8 P15
1/25/2024
Let the letters
F
F
F
,
L
L
L
,
Y
Y
Y
,
B
B
B
,
U
U
U
,
G
G
G
represent different digits. Suppose
F
‾
L
‾
Y
‾
F
‾
L
‾
Y
‾
\underline{F}\underline{L}\underline{Y}\underline{F}\underline{L}\underline{Y}
F
L
Y
F
L
Y
is the largest number that satisfies the equation
8
⋅
F
‾
L
‾
Y
‾
F
‾
L
‾
Y
‾
=
B
‾
U
‾
G
‾
B
‾
U
‾
G
‾
.
8 \cdot \underline{F}\underline{L}\underline{Y}\underline{F}\underline{L}\underline{Y} = \underline{B}\underline{U}\underline{G}\underline{B}\underline{U}\underline{G}.
8
⋅
F
L
Y
F
L
Y
=
B
U
G
B
U
G
.
What is the value of
F
‾
L
‾
Y
‾
+
B
‾
U
‾
G
‾
\underline{F}\underline{L}\underline{Y} + \underline{B}\underline{U}\underline{G}
F
L
Y
+
B
U
G
?
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
A
)
<
/
s
p
a
n
>
1089
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
B
)
<
/
s
p
a
n
>
1098
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
C
)
<
/
s
p
a
n
>
1107
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
D
)
<
/
s
p
a
n
>
1116
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
E
)
<
/
s
p
a
n
>
1125
<span class='latex-bold'>(A) </span> 1089\qquad<span class='latex-bold'>(B) </span> 1098\qquad<span class='latex-bold'>(C) </span> 1107\qquad<span class='latex-bold'>(D) </span> 1116\qquad<span class='latex-bold'>(E) </span> 1125
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
A
)
<
/
s
p
an
>
1089
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
B
)
<
/
s
p
an
>
1098
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
C
)
<
/
s
p
an
>
1107
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
D
)
<
/
s
p
an
>
1116
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
E
)
<
/
s
p
an
>
1125
AMC
2024 AMC 8
AMC 8