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24

Part of 1999 AMC 8

Problems(1)

1999 AMC 8 #24

Source:

6/17/2011
When 199920001999{}^2{}^0{}^0{}^0 is divided by 55 , the remainder is
(A) 4(B) 1(C) 2(D) 3(E) 0 \text{(A)}\ 4\qquad\text{(B)}\ 1\qquad\text{(C)}\ 2\qquad\text{(D)}\ 3\qquad\text{(E)}\ 0