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Contests
National and Regional Contests
USA Contests
MAA AMC
AMC 12/AHSME
1993 AMC 12/AHSME
2
2
Part of
1993 AMC 12/AHSME
Problems
(1)
1993 AMC 12 #2 - Triangle
Source:
1/2/2012
In
△
A
B
C
\triangle ABC
△
A
BC
,
∠
A
=
5
5
∘
\angle A=55^{\circ}
∠
A
=
5
5
∘
,
∠
C
=
7
5
∘
\angle C=75^{\circ}
∠
C
=
7
5
∘
,
D
D
D
is on side
A
B
‾
\overline{AB}
A
B
and
E
E
E
is on side
B
C
‾
\overline{BC}
BC
. If
D
B
=
B
E
DB=BE
D
B
=
BE
, then
∠
B
E
D
=
\angle BED=
∠
BE
D
=
[asy] size((100)); draw((0,0)--(10,0)--(8,10)--cycle); draw((4,5)--(9.2,4)); dot((0,0)); dot((10,0)); dot((8,10)); dot((4,5)); dot((9.2,4)); label("A", (0,0), SW); label("B", (8,10), N); label("C", (10,0), SE); label("D", (4,5), NW); label("E", (9.2,4), E); label("
5
5
∘
55^{\circ}
5
5
∘
", (.5,0), NE); label("
7
5
∘
75^{\circ}
7
5
∘
", (9.8,0), NW); [/asy]
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<span class='latex-bold'>(A)</span>\ 50^{\circ} \qquad<span class='latex-bold'>(B)</span>\ 55^{\circ} \qquad<span class='latex-bold'>(C)</span>\ 60^{\circ} \qquad<span class='latex-bold'>(D)</span>\ 65^{\circ} \qquad<span class='latex-bold'>(E)</span>\ 70^{\circ}
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>
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)
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>
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0
∘
AMC