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Contests
National and Regional Contests
USA Contests
MAA AMC
AMC 12/AHSME
1968 AMC 12/AHSME
16
16
Part of
1968 AMC 12/AHSME
Problems
(1)
Which is True?
Source: 1968 AHSME Problem #16
9/7/2011
If
x
x
x
is such that
1
x
<
2
\dfrac{1}{x}<2
x
1
<
2
and
1
x
>
−
3
\dfrac{1}{x}>-3
x
1
>
−
3
, then:
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
A
)
<
/
s
p
a
n
>
−
1
3
<
x
<
1
2
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
B
)
<
/
s
p
a
n
>
−
1
2
<
x
<
3
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
C
)
<
/
s
p
a
n
>
x
>
1
2
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
D
)
<
/
s
p
a
n
>
x
>
1
2
or
−
1
3
<
x
<
0
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
E
)
<
/
s
p
a
n
>
x
>
1
2
or
x
<
−
1
3
<span class='latex-bold'>(A)</span>\ -\dfrac{1}{3}<x<\dfrac{1}{2} \qquad <span class='latex-bold'>(B)</span>\ -\dfrac{1}{2}<x<3 \qquad <span class='latex-bold'>(C)</span>\ x>\dfrac{1}{2} \qquad\\ <span class='latex-bold'>(D)</span>\ x>\dfrac{1}{2}\text{ or }-\dfrac{1}{3}<x<0 \qquad <span class='latex-bold'>(E)</span>\ x>\dfrac{1}{2}\text{ or }x<-\dfrac{1}{3}
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
A
)
<
/
s
p
an
>
−
3
1
<
x
<
2
1
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
B
)
<
/
s
p
an
>
−
2
1
<
x
<
3
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
C
)
<
/
s
p
an
>
x
>
2
1
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
D
)
<
/
s
p
an
>
x
>
2
1
or
−
3
1
<
x
<
0
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
E
)
<
/
s
p
an
>
x
>
2
1
or
x
<
−
3
1
AMC