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National and Regional Contests
USA Contests
MAA AMC
AMC 12/AHSME
1950 AMC 12/AHSME
1
1
Part of
1950 AMC 12/AHSME
Problems
(1)
AHSME 1950-the original problems
Source:
7/17/2008
If 64 is divided into three parts proportional to 2, 4, and 6, the smallest part is:
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5
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11
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10
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None of these answers
<span class='latex-bold'>(A)</span>\ 5\dfrac{1}{3} \qquad <span class='latex-bold'>(B)</span>\ 11 \qquad <span class='latex-bold'>(C)</span>\ 10\dfrac{2}{3} \qquad <span class='latex-bold'>(D)</span>\ 5 \qquad <span class='latex-bold'>(E)</span>\ \text{None of these answers}
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11
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E
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None of these answers
ratio