MathDB

8

Part of 2012 AMC 10

Problems(2)

Sums by Pairs

Source: 2012 AMC 12A Problem #6 and AMC 10A Problem #8

2/8/2012
The sums of three whole numbers taken in pairs are 1212, 1717, and 1919. What is the middle number?
<spanclass=′latex−bold′>(A)</span> 4<spanclass=′latex−bold′>(B)</span> 5<spanclass=′latex−bold′>(C)</span> 6<spanclass=′latex−bold′>(D)</span> 7<spanclass=′latex−bold′>(E)</span> 8 <span class='latex-bold'>(A)</span>\ 4\qquad<span class='latex-bold'>(B)</span>\ 5\qquad<span class='latex-bold'>(C)</span>\ 6\qquad<span class='latex-bold'>(D)</span>\ 7\qquad<span class='latex-bold'>(E)</span>\ 8
AMC
Sum of Integer Solutions

Source: 2012 AMC10B Problem #8

2/23/2012
What is the sum of all integer solutions to 1<(x−2)2<251<(x-2)^2<25?
<spanclass=′latex−bold′>(A)</span> 10<spanclass=′latex−bold′>(B)</span> 12<spanclass=′latex−bold′>(C)</span> 15<spanclass=′latex−bold′>(D)</span> 19<spanclass=′latex−bold′>(E)</span> 25 <span class='latex-bold'>(A)</span>\ 10\qquad<span class='latex-bold'>(B)</span>\ 12\qquad<span class='latex-bold'>(C)</span>\ 15\qquad<span class='latex-bold'>(D)</span>\ 19\qquad<span class='latex-bold'>(E)</span>\ 25
inequalitiesAMC