MathDB

2014.8

Part of Ukrainian TYM Qualifying - geometry

Problems(1)

equal angles wanted and given, right angle for point on median

Source: 2014 XVII All-Ukrainian Tournament of Young Mathematicians named after M. Y. Yadrenko, Qualifying p8

5/7/2021
In the triangle ABCABC on the ray BABA mark the point KK so that ∠BCA=∠KCA\angle BCA= \angle KCA , and on the median BMBM mark the point TT so that ∠CTK=90o\angle CTK=90^o . Prove that ∠MTC=∠MCB\angle MTC=\angle MCB .
geometryequal anglesUkrainian TYM