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Problems
Contests
National and Regional Contests
Poland Contests
Polish MO Finals
1958 Polish MO Finals
1958 Polish MO Finals
Part of
Polish MO Finals
Subcontests
(6)
6
1
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min perimeter of tangential quad
Prove that of all the quadrilaterals circuscribed around a given circle, the square has the smallest perimeter.
5
1
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plane bisector of any dihedral angle in tetrahedron
Prove the theorem: In a tetrahedron, the plane bisector of any dihedral angle divides the opposite edge into segments proportional to the areas of the tetrahedron faces that form this dihedral angle.
4
1
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(1 + x)(1 + x^2) (1 + x^4) ...(1 + x^{2^k}) = 1 + x + x^2 + x^3+ .. x^m
Prove that if
k
k
k
is a natural number, then
(
1
+
x
)
(
1
+
x
2
)
(
1
+
x
4
)
…
(
1
+
x
2
k
)
=
1
+
x
+
x
2
+
x
3
+
…
+
x
m
(1 + x)(1 + x^2) (1 + x^4) \ldots (1 + x^{2^k}) =1 + x + x^2 + x^3+ \ldots + x^m
(
1
+
x
)
(
1
+
x
2
)
(
1
+
x
4
)
…
(
1
+
x
2
k
)
=
1
+
x
+
x
2
+
x
3
+
…
+
x
m
where
m
m
m
is a natural number dependent on
k
k
k
; determine
m
m
m
.
3
1
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cos 2\pi / n + cos 4\pi / n + cos 6\pi/ n +...+ \cos 2n \pi/n =0
Prove that if
n
n
n
is a natural number greater than
1
1
1
, then
cos
2
π
n
+
cos
4
π
n
+
cos
6
π
n
+
…
+
cos
2
n
π
n
=
0.
\cos \frac{2\pi}{n} + \cos \frac{4\pi}{n} + \cos \frac{6\pi}{n} + \ldots + \cos \frac{2n \pi}{n} = 0.
cos
n
2
π
+
cos
n
4
π
+
cos
n
6
π
+
…
+
cos
n
2
nπ
=
0.
2
1
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center of gravity of quad coincide
Each side of a convex quadrilateral
A
B
C
D
ABCD
A
BC
D
is divided into three equal parts; a straight line is drawn through the dividing points of sides
A
B
AB
A
B
and
A
D
AD
A
D
that lie closer to vertex
A
A
A
, and similarly for vertices
B
B
B
,
C
C
C
,
D
D
D
. Prove that the center of gravity of the quadrilateral formed by the drawn lines coincides with the center of gravity of quadrilateral
A
B
C
D
ABCD
A
BC
D
.
1
1
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504 / product of 2 consecutive swith middle = n^3
Prove that the product of three consecutive natural numbers, the middle of which is the cube of a natural number, is divisible by
504
504
504
.