MathDB

Problems(4)

functional equation

Source: 2016 Korea Winter Program Test1 Day1 #3

1/25/2016
Determine all the functions f:RRf : \mathbb{R}\rightarrow\mathbb{R} that satisfies the following.
f(xf(y)+yf(z)+zf(x))=yf(x)+zf(y)+xf(z)f(xf(y)+yf(z)+zf(x))=yf(x)+zf(y)+xf(z)
functional equationalgebraalgebra proposed
Writing Number on Balls

Source: 2016 Korea Winter Program Test2 Day1 #3

1/25/2016
p,q,rp, q, r are natural numbers greater than 1.
There are pqpq balls placed on a circle, and one number among 0,1,2,,pr10, 1, 2, \cdots , pr-1 is written on each ball, satisfying following conditions.
(1) If ii and jj is written on two adjacent balls, ij=1|i-j|=1 or ij=pr1|i-j|=pr-1. (2) ii is written on a ball AA. If we skip q1q-1 balls clockwise from AA and see qthq^{th} ball, i+ri+r or i(p1)ri-(p-1)r is written on it. (This condition is satisfied for every ball.)
If pp is even, prove that the number of pairs of two adjacent balls with 11 and 22 written on it is odd.
combinatoricscombinatorics proposed
Lots and lots of circles

Source: 2016 Korea Winter Camp 1st Test #7

1/25/2016
There are three circles w1,w2,w3w_1, w_2, w_3. Let wi+1wi+2=Ai,Biw_{i+1} \cap w_{i+2} = A_i, B_i, where AiA_i lies insides of wiw_i. Let γ\gamma be the circle that is inside w1,w2,w3w_1,w_2,w_3 and tangent to the three said circles at T1,T2,T3T_1, T_2, T_3. Let TiAi+1Ti+2T_iA_{i+1}T_{i+2}'s circumcircle and TiAi+2Ti+1T_iA_{i+2}T_{i+1}'s circumcircle meet at SiS_i. Prove that the circumcircles of AiBiSiA_iB_iS_i meet at two points. (1i31 \le i \le 3, indices taken modulo 33)
If one of Ai,Bi,SiA_i,B_i,S_i are collinear - the intersections of the other two circles lie on this line. Prove this as well.
geometry
Weighted Fermat

Source: 2016 Korean Winter Camp 2nd Test #7

1/25/2016
Let there be a triangle ABC\triangle ABC with BC=aBC=a, CA=bCA=b, AB=cAB=c. Let TT be a point not inside ABC\triangle ABC and on the same side of AA with respect to BCBC, such that BTCT=cbBT-CT=c-b. Let n=BTn=BT and m=CTm=CT. Find the point PP that minimizes f(P)=aAP+mBP+nCPf(P)=-a \cdot AP + m \cdot BP + n \cdot CP.
geometryalgebraconics