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Today's Calculation Of Integral
2013 Today's Calculation Of Integral
889
889
Part of
2013 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 889
Source: 2013 Okayama University entrance exam/Science
10/2/2013
Find the area
S
S
S
of the region enclosed by the curve
y
=
∣
x
−
1
x
∣
(
x
>
0
)
y=\left|x-\frac{1}{x}\right|\ (x>0)
y
=
x
−
x
1
(
x
>
0
)
and the line
y
=
2
y=2
y
=
2
.
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integration
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logarithms
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