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Today's Calculation Of Integral
2013 Today's Calculation Of Integral
861
861
Part of
2013 Today's Calculation Of Integral
Problems
(1)
Today's calculation of Integral 861
Source: 2013 Showa university entrance exam/Medicine
1/25/2013
Answer the questions as below.(1) Find the local minimum of
y
=
x
(
1
ā
x
2
)
e
x
2
.
y=x(1-x^2)e^{x^2}.
y
=
x
(
1
ā
x
2
)
e
x
2
.
(2) Find the total area of the part bounded the graph of the function in (1) and the
x
x
x
-axis.
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integration
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