We are given a triangle ABC such that ∠BAC<90∘. The point D is on the opposite side of the line AB to C such that ∣AD∣=∣BD∣ and ∠ADB=90∘. Similarly, the point E is on the opposite side of AC to B such that ∣AE∣=∣CE∣ and ∠AEC=90∘. The point X is such that ADXE is a parallelogram.Prove that ∣BX∣=∣CX∣. geometryparallelogramcongruent triangles