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Chile Classification NMO
1996 Chile Classification NMO
1996 Chile Classification NMO
Part of
Chile Classification NMO
Subcontests
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1996 Chile Classification / Qualifying NMO VIII
p1. Prove that the numbers
49
49
49
,
4489
4489
4489
,
444889
444889
444889
,
.
.
.
...
...
, obtained by placing the number
48
48
48
in the middle of the previous one, are squares of integer numbers. p2. Let's consider a cube with a side
18
18
18
cm. In the center of three different and non-opposite faces, we make a rectangular hole with a side
6
6
6
cm , which crosses to the opposite face, obtaining the figure on the right. Determine the area of this body. https://cdn.artofproblemsolving.com/attachments/9/e/f4ae672c26ad9d8f8e3493393fabc6f5544151.png p3. Prove that it is possible to find a right angle and an isosceles triangle, both with sides integers, equal perimeter and equal area. p4. Consider the nine regions
R
1
.
,
R
2
,
.
.
.
,
R
9
R_1., R_2, ..., R_9
R
1
.
,
R
2
,
...
,
R
9
that are formed by the five olympic rings, as a sample in the figure. In each region a number from
1
1
1
to
9
9
9
is placed, without repeating, so that the sum in each ring it's the same. What is the largest and the smallest value for this sum? https://cdn.artofproblemsolving.com/attachments/0/e/f7ed45eb647f411be5ae4bffbf2aef5da17f38.png p5. Determine the period of
0
,
19
‾
+
0
,
199
‾
0,\overline{19} + 0,\overline{199}
0
,
19
+
0
,
199
and of
0
,
19
‾
⋅
0
,
199
‾
0,\overline{19}\cdot 0,\overline{199}
0
,
19
⋅
0
,
199
. p6. Let
A
B
C
D
ABCD
A
BC
D
be a square and
E
E
E
a point inside it, such that the
E
C
D
ECD
EC
D
is isosceles at
C
C
C
. Prove that there exists a point
E
E
E
inside the square for which, also, the
A
E
B
AEB
A
EB
is isosceles at
E
E
E
. p7. Let us consider the set
S
=
{
1
,
2
,
.
.
.
,
n
}
S = \{1, 2,...,n\}
S
=
{
1
,
2
,
...
,
n
}
. Let
M
1
,
M
2
,
.
.
.
,
M
n
+
1
M_1, M_2,..., M_{n + 1}
M
1
,
M
2
,
...
,
M
n
+
1
, be non-empty subsets of
S
S
S
. Prove that there are different indices
r
,
s
,
r
+
s
,
i
1
,
i
2
,
.
.
.
,
i
r
,
j
1
,
j
2
,
.
.
.
,
j
s
r, s, r + s, i_1, i_2 ,... ,i_r,j_1, j_2, ..., j_s
r
,
s
,
r
+
s
,
i
1
,
i
2
,
...
,
i
r
,
j
1
,
j
2
,
...
,
j
s
such that
M
i
1
∪
.
.
.
∪
M
i
r
=
M
j
1
∪
.
.
.
∪
M
j
s
M_{i1}\cup ... \cup M_{ir} = M_{j1} \cup ... \cup M_{js}
M
i
1
∪
...
∪
M
i
r
=
M
j
1
∪
...
∪
M
j
s
.