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Chile Classification NMO Juniors
2006 Chile Classification NMO Juniors
2006 Chile Classification NMO Juniors
Part of
Chile Classification NMO Juniors
Subcontests
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2006 Chile Classification / Qualifying NMO Juniors XVIII
p1. Let
a
,
b
a, b
a
,
b
different real numbers such that
a
b
+
a
+
10
b
b
+
10
a
=
2
\frac{a}{b} +\frac{a + 10b}{b + 10a}= 2
b
a
+
b
+
10
a
a
+
10
b
=
2
. Find
a
b
\frac{a}{b}
b
a
[url=https://artofproblemsolving.com/community/c4h1846788p12438105]p2. The vertex
E
E
E
of a square
E
F
G
H
EFGH
EFG
H
with side
2006
2006
2006
mm is in the center of the square
A
B
C
D
ABCD
A
BC
D
with side
10
10
10
mm. Segment
E
F
EF
EF
intersects
C
D
CD
C
D
at point
I
I
I
. Segment
E
H
EH
E
H
intersects
A
D
AD
A
D
at
J
J
J
. If
∠
E
I
D
=
6
0
o
\angle EID = 60^o
∠
E
I
D
=
6
0
o
, find the area of the quadrilateral
E
I
D
J
EIDJ
E
I
D
J
. p3. The number
30
a
0
b
03
‾
\overline{30a0b03}
30
a
0
b
03
in decimal notation is divisible by
13
13
13
. Find the possible values of the digits
a
,
b
a, b
a
,
b
. p4. In a rectangular board of
2006
2006
2006
squares, distributed in
34
34
34
rows and
59
59
59
columns, they will be placed three identical buttons in the center of the boxes, determining a triangle. In how many different ways can we can place the buttons forming a ractangle triangle with legs parallel to the edges of the board? [url=https://artofproblemsolving.com/community/c4h1846785p12438094]p5. Let
△
A
B
C
\vartriangle ABC
△
A
BC
be any triangle and
△
M
N
P
\vartriangle MNP
△
MNP
be the triangle formed by the points of tangency of the inscribed circle with the sides of the triangle
△
A
B
C
\vartriangle ABC
△
A
BC
, show that if
△
M
N
P
\vartriangle MNP
△
MNP
is equilateral, then
△
A
B
C
\vartriangle ABC
△
A
BC
is equilateral. p6. A natural number is called a palindrome, when the same number is obtained by writing its digits in reverse order, for example
23432
23432
23432
,
565
565
565
,
8
8
8
are palindromes. Determine all pairs of positive integers
m
,
n
m, n
m
,
n
such that
1111...11
⏟
m
t
i
m
e
s
⋅
1111...11
⏟
n
t
i
m
e
s
\underbrace{1111...11} _{m \,\, times} \cdot \underbrace{1111...11}_{n \,\, times}
m
t
im
es
1111...11
⋅
n
t
im
es
1111...11
is palindrome.