Let ABC be a triangle . The internal bisector of ABC intersects the side AC at L and the circumcircle of ABC again at W=B. Let K be the perpendicular projection of L onto AW. the circumcircle of BLC intersects line CK again at P=C. Lines BP and AW meet at point T. Prove that AW=WT. geometrycircumcircleMEMO 2018