6
Part of 1967 IMO Shortlist
Problems(8)
IMO LongList 1967, Bulgaria 6
Source: IMO LongList 1967, Bulgaria 6
12/16/2004
Solve the system of equations:
linear algebramatrixalgebrasystem of equationsIMO ShortlistIMO Longlist
IMO LongList 1967, Mongolia 6
Source: IMO LongList 1967, Mongolia 6
12/16/2004
Prove the identity for any natural number and any angle
trigonometryalgebraseries summationTrigonometric IdentitiesIMO ShortlistIMO Longlist
IMO LongList 1967, Hungary 6
Source: IMO LongList 1967, Hungary 6
12/16/2004
Three disks of diameter are touching a sphere in their centers. Besides, every disk touches the other two disks. How to choose the radius of the sphere in order that axis of the whole figure has an angle of with the line connecting the center of the sphere with the point of the disks which is at the largest distance from the axis ? (The axis of the figure is the line having the property that rotation of the figure of around that line brings the figure in the initial position. Disks are all on one side of the plane, passing through the center of the sphere and orthogonal to the axis).
geometry3D geometrysphereanglesIMO ShortlistIMO Longlist
IMO LongList 1967, Poland 6
Source: IMO LongList 1967, Poland 6
12/16/2004
A line is drawn through the intersection point of altitudes of acute-angle triangles. Prove that symmetric images of with respect to the sides have one point in common, which lies on the circumcircle of
geometrycircumcirclereflectionTriangleconcurrencyIMO ShortlistIMO Longlist
IMO LongList 1967, Romania 6
Source: IMO LongList 1967, Romania 6
12/16/2004
Prove the following inequality:
where
Inequalitypolynomialalgebran-variable inequality
IMO LongList 1967, Socialists Republic Of Czechoslovakia 6
Source: IMO LongList 1967, Socialists Republic Of Czechoslovakia 6
12/16/2004
Given a segment of the length 1, define the set of points in the
following way: it contains two points and also all points obtained from by iterating the following rule: With every pair of points the set contains also the point of the segment for which
geometrypoint setSequenceIMO ShortlistIMO Longlist
IMO LongList 1967, Sweden 6
Source: IMO LongList 1967, Sweden 6
12/16/2004
In making Euclidean constructions in geometry it is permitted to use a ruler and a pair of compasses. In the constructions considered in this question no compasses are permitted, but the ruler is assumed to have two parallel edges, which can be used for constructing two parallel lines through two given points whose distance is at least equal to the breadth of the rule. Then the distance between the parallel lines is equal to the breadth of the ruler. Carry through the following constructions with such a ruler. Construct:
a) The bisector of a given angle.
b) The midpoint of a given rectilinear line segment.
c) The center of a circle through three given non-collinear
points.
d) A line through a given point parallel to a given line.
geometryconstructionbisectormidpointCenterIMO ShortlistIMO Longlist
IMO LongList 1967, Soviet Union 6
Source: IMO LongList 1967, Soviet Union 6
12/16/2004
On the circle with center 0 and radius 1 the point is fixed and points are distributed in such a way that the angle (in radians). Cut the circle at points How many arcs with different lengths are obtained. ?
combinatoricsgeometrycountingcircleIMO ShortlistIMO Longlist