MathDB

Problems(8)

IMO LongList 1967, Bulgaria 6

Source: IMO LongList 1967, Bulgaria 6

12/16/2004
Solve the system of equations: x+y+1x=6x+y+1+1y=4. \begin{matrix} |x+y| + |1-x| = 6 \\ |x+y+1| + |1-y| = 4. \end{matrix}
linear algebramatrixalgebrasystem of equationsIMO ShortlistIMO Longlist
IMO LongList 1967, Mongolia 6

Source: IMO LongList 1967, Mongolia 6

12/16/2004
Prove the identity k=0n(nk)(tanx2)2k(1+2k(1tan2x2)k)=sec2nx2+secnx\sum\limits_{k=0}^n\binom{n}{k}\left(\tan\frac{x}{2}\right)^{2k}\left(1+\frac{2^k}{\left(1-\tan^2\frac{x}{2}\right)^k}\right)=\sec^{2n}\frac{x}{2}+\sec^n x for any natural number nn and any angle x.x.
trigonometryalgebraseries summationTrigonometric IdentitiesIMO ShortlistIMO Longlist
IMO LongList 1967, Hungary 6

Source: IMO LongList 1967, Hungary 6

12/16/2004
Three disks of diameter dd are touching a sphere in their centers. Besides, every disk touches the other two disks. How to choose the radius RR of the sphere in order that axis of the whole figure has an angle of 6060^\circ with the line connecting the center of the sphere with the point of the disks which is at the largest distance from the axis ? (The axis of the figure is the line having the property that rotation of the figure of 120120^\circ around that line brings the figure in the initial position. Disks are all on one side of the plane, passing through the center of the sphere and orthogonal to the axis).
geometry3D geometrysphereanglesIMO ShortlistIMO Longlist
IMO LongList 1967, Poland 6

Source: IMO LongList 1967, Poland 6

12/16/2004
A line ll is drawn through the intersection point HH of altitudes of acute-angle triangles. Prove that symmetric images la,lb,lcl_a, l_b, l_c of ll with respect to the sides BC,CA,ABBC,CA,AB have one point in common, which lies on the circumcircle of ABC.ABC.
geometrycircumcirclereflectionTriangleconcurrencyIMO ShortlistIMO Longlist
IMO LongList 1967, Romania 6

Source: IMO LongList 1967, Romania 6

12/16/2004
Prove the following inequality: i=1kxii=1kxin1i=1kxin+k1,\prod^k_{i=1} x_i \cdot \sum^k_{i=1} x^{n-1}_i \leq \sum^k_{i=1} x^{n+k-1}_i, where xi>0,x_i > 0, kN,nN.k \in \mathbb{N}, n \in \mathbb{N}.
Inequalitypolynomialalgebran-variable inequality
IMO LongList 1967, Socialists Republic Of Czechoslovakia 6

Source: IMO LongList 1967, Socialists Republic Of Czechoslovakia 6

12/16/2004
Given a segment ABAB of the length 1, define the set MM of points in the following way: it contains two points A,B,A,B, and also all points obtained from A,BA,B by iterating the following rule: With every pair of points X,YX,Y the set MM contains also the point ZZ of the segment XYXY for which YZ=3XZ.YZ = 3XZ.
geometrypoint setSequenceIMO ShortlistIMO Longlist
IMO LongList 1967, Sweden 6

Source: IMO LongList 1967, Sweden 6

12/16/2004
In making Euclidean constructions in geometry it is permitted to use a ruler and a pair of compasses. In the constructions considered in this question no compasses are permitted, but the ruler is assumed to have two parallel edges, which can be used for constructing two parallel lines through two given points whose distance is at least equal to the breadth of the rule. Then the distance between the parallel lines is equal to the breadth of the ruler. Carry through the following constructions with such a ruler. Construct: a) The bisector of a given angle. b) The midpoint of a given rectilinear line segment. c) The center of a circle through three given non-collinear points. d) A line through a given point parallel to a given line.
geometryconstructionbisectormidpointCenterIMO ShortlistIMO Longlist
IMO LongList 1967, Soviet Union 6

Source: IMO LongList 1967, Soviet Union 6

12/16/2004
On the circle with center 0 and radius 1 the point A0A_0 is fixed and points A1,A2,,A999,A1000A_1, A_2, \ldots, A_{999}, A_{1000} are distributed in such a way that the angle A00Ak=k\angle A_00A_k = k (in radians). Cut the circle at points A0,A1,,A1000.A_0, A_1, \ldots, A_{1000}. How many arcs with different lengths are obtained. ?
combinatoricsgeometrycountingcircleIMO ShortlistIMO Longlist