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Problems(2)

On 100 strictly increasing sequences of positive integers

Source: 3-rd Hungary-Israel Binational Mathematical Competition 1992

5/24/2007
We are given 100100 strictly increasing sequences of positive integers: Ai=(a1(i),a2(i),...),i=1,2,...,100A_{i}= (a_{1}^{(i)}, a_{2}^{(i)},...), i = 1, 2,..., 100. For 1r,s1001 \leq r, s \leq 100 we define the following quantities: fr(u)=f_{r}(u)= the number of elements of ArA_{r} not exceeding nn; fr,s(u)=f_{r,s}(u) = the number of elements of ArAsA_{r}\cap A_{s} not exceeding nn. Suppose that fr(n)12nf_{r}(n) \geq\frac{1}{2}n for all rr and nn. Prove that there exists a pair of indices (r,s)(r, s) with rsr \not = s such that fr,s(n)8n33f_{r,s}(n) \geq\frac{8n}{33} for at least five distinct nsn-s with 1n<19920.1 \leq n < 19920.
combinatorics unsolvedcombinatorics
r-Fibonacci number

Source: 3-rd Hungary-Israel Binational Mathematical Competition 1992

5/24/2007
We examine the following two sequences: The Fibonacci sequence: F0=0,F1=1,Fn=Fn1+Fn2F_{0}= 0, F_{1}= 1, F_{n}= F_{n-1}+F_{n-2 } for n2n \geq 2; The Lucas sequence: L0=2,L1=1,Ln=Ln1+Ln2L_{0}= 2, L_{1}= 1, L_{n}= L_{n-1}+L_{n-2} for n2n \geq 2. It is known that for all n0n \geq 0 Fn=αnβn5,Ln=αn+βn,F_{n}=\frac{\alpha^{n}-\beta^{n}}{\sqrt{5}},L_{n}=\alpha^{n}+\beta^{n}, where α=1+52,β=152\alpha=\frac{1+\sqrt{5}}{2},\beta=\frac{1-\sqrt{5}}{2}. These formulae can be used without proof. We call a nonnegative integer rr-Fibonacci number if it is a sum of rr (not necessarily distinct) Fibonacci numbers. Show that there infinitely many positive integers that are not rr-Fibonacci numbers for any r,1r5.r, 1 \leq r\leq 5.
logarithmsnumber theory proposednumber theory