Roots of Equation
Source:
February 7, 2009
Problem Statement
The roots of the equation 2\sqrt {x} \plus{} 2x^{ \minus{} \frac {1}{2}} \equal{} 5 can be found by solving:
(A)\ 16x^2 \minus{} 92x \plus{} 1 \equal{} 0 \qquad (B)\ 4x^2 \minus{} 25x \plus{} 4 \equal{} 0 \qquad (C)\ 4x^2 \minus{} 17x \plus{} 4 \equal{} 0 \\
(D)\ 2x^2 \minus{} 21x \plus{} 2 \equal{} 0 \qquad (E)\ 4x^2 \minus{} 25x \minus{} 4 \equal{} 0