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min p, smallest prime divisor of n when s=a+b=a^2+b^2=m/n

Source: 2016 Argentina OMA Finals L3 p5

January 16, 2023
number theoryprime divisorsdivisoralgebra

Problem Statement

Let aa and bb be rational numbers such that a+b=a2+b2a+b=a^2+b^2 . Suppose the common value s=a+b=a2+b2s=a+b=a^2+b^2 is not an integer, and let's write it as an irreducible fraction: s=mns=\frac{m}{n}. Let pp be the smallest prime divisor of nn. Find the minimum value of pp.