If a number eight times as large as x is increased by two, then one fourth of the result equals<spanclass=′latex−bold′>(A)</span>2x+21<spanclass=′latex−bold′>(B)</span>x+21<spanclass=′latex−bold′>(C)</span>2x+2<spanclass=′latex−bold′>(D)</span>2x+4<spanclass=′latex−bold′>(E)</span>2x+16