MathDB
Today's calculation of Integral 631

Source:

July 9, 2010
calculusintegrationlogarithmscalculus computations

Problem Statement

Evaluate 23(x2+x41)(1x2+1+1x21)dx.\int_{\sqrt{2}}^{\sqrt{3}} (x^2+\sqrt{x^4-1})(\frac{1}{\sqrt{x^2+1}}+{\frac{1}{\sqrt{x^2-1}})dx.}
Proposed by kunny