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Putnam
1991 Putnam
B6
sinh inequality
sinh inequality
Source: Putnam 1991 B6
August 21, 2021
inequalities
Problem Statement
Let
a
a
a
and
b
b
b
be positive numbers. Find the largest number
c
c
c
, in terms of
a
a
a
and
b
b
b
, such that for all
x
x
x
with
0
<
∣
x
∣
≤
c
0<|x|\le c
0
<
∣
x
∣
≤
c
and for all
α
\alpha
α
with
0
<
α
<
1
0<\alpha<1
0
<
α
<
1
, we have:
a
α
b
1
−
α
≤
a
sinh
α
x
sinh
x
+
b
sinh
x
(
1
−
α
)
sinh
x
.
a^\alpha b^{1-\alpha}\le\frac{a\sinh\alpha x}{\sinh x}+\frac{b\sinh x(1-\alpha)}{\sinh x}.
a
α
b
1
−
α
≤
sinh
x
a
sinh
αx
+
sinh
x
b
sinh
x
(
1
−
α
)
.
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