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6
SMT 2022 Algebra #6
SMT 2022 Algebra #6
Source:
March 27, 2023
Problem Statement
Compute
cot
(
∑
n
=
1
23
cot
−
1
(
1
+
∑
k
=
1
n
2
k
)
)
.
\cot\left(\sum_{n=1}^{23}\cot^{-1}\left(1+\sum_{k=1}^n2k\right)\right).
cot
(
n
=
1
∑
23
cot
−
1
(
1
+
k
=
1
∑
n
2
k
)
)
.
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