MathDB
Another geo with angle 60

Source: Oral Moscow geometry olympiad 2023 8-9.5

April 20, 2023
geometry

Problem Statement

Altitudes BB1BB_1 and CC1CC_1 of acute triangle ABCABC intersect at HH, and A=60o\angle A = 60^{o}, AB<ACAB < AC. The median AMAM intersects the circumcircle of ABCABC at point KK; LL is the midpoint of the arc BCBC of the circumcircle that does not contain point AA; lines B1C1B_1C_1 and BCBC intersect at point EE. Prove that EHL=ABK\angle EHL = \angle ABK.