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\left[\frac{x^2+1}{x}\right]-\left[\frac{x}{x^2+1}\right]=3

Source: Moldova EGMO TST 2023

February 4, 2023
number theory

Problem Statement

Solve the equation [x2+1x][xx2+1]=3.\left[\frac{x^2+1}{x}\right]-\left[\frac{x}{x^2+1}\right]=3.