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(x+100) (x+99) ... (x-99)(x-100)=x^{201}+... (VII Soros Olympiad 2000-01 R1 8.7)

Source:

July 27, 2021
algebrapolynomial

Problem Statement

In the expression (x+100)(x+99)...(x99)(x100)(x + 100) (x + 99) ... (x-99) (x-100), the brackets were expanded and similar terms were given. The expression x201+...+ax2+bx+cx^{201} + ...+ ax^2 + bx + c turned out. Find the numbers aa and cc.