\sum_{i=1}^{k} b_i = k \cdot b_k + \sum_{j=b_{k+1}}^{n} a_j, sequences
Source: 2008 Dutch IMO TST P3
January 10, 2020
combinatoricsSequenceSum
Problem Statement
Let be positive integers. Consider a sequence of positive integers that satisfies m = a_1 \ge a_2\ge ... \ge a_n \ge 1. Then define, for 1\le i\le m, # \{ j \in \{1, 2, ... , n\}: a_j \ge i\},
so is the number of terms of the given sequence for which a_j \ge i.
Similarly, we define, for 1\le j \le n, # \{ i \in \{1, 2, ... , m\}: b_i \ge j\} , thus is the number of terms bi in the given sequence for which b_i \ge j.
E.g.: If is the sequence then is the sequence .
(a) Prove that for 1 \le j \le n.
(b) Prove that for 1\le k \le m: .