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Today's Calculation Of Integral
2011 Today's Calculation Of Integral
733
Today's calculation of Integral 733
Today's calculation of Integral 733
Source: 2011 Hirosaki University entrance exam/Medicine etc.
July 3, 2011
calculus
integration
limit
calculus computations
Problem Statement
Find
lim
n
→
∞
∫
0
1
x
2
e
−
(
x
n
)
2
d
x
.
\lim_{n\to\infty} \int_0^1 x^2e^{-\left(\frac{x}{n}\right)^2}dx.
lim
n
→
∞
∫
0
1
x
2
e
−
(
n
x
)
2
d
x
.
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